Site location is 20° N
Find tilt angle when sun is over:
Equator
Tropic of Cancer
Tropic of Capricorn
Solar panel always faces the sun.
Sun line is the line from sun to solar panel bottom
If the site locates exactly on Equator/ Tropic of Cancer/ Tropic of Capricorn
Solar panel lies horizontal to face the sun
Sun line = Vertical line from template to sun
θ = angle between equator --> sun line = latitude of site
Since the site is 20° N, so θ = 20°
α = angle between template --> sun line = solar altitude angle at site
α = 90° - θ (Site at Equator)
α = 90° - θ - 23.45 (Site at different hemisphere with sun)
α = 90° - θ + 23.45 (Site at same hemisphere with sun)
Final answer:
If α < 90° : α looking [opposite hemisphere of site]
If α > 90° : However, physically this actually means α = [180 - α ] looking [same hemisphere of site]
β = angle between template --> back of solar panel = tilt angle
β = 180° - 90° - α = 90° - α (Normal right triangle calculation)
Final answer:
β looking [opposite hemisphere of site]
In general, usually looking direction of β and α are same.
When sun is over Equator,
α = 90° - 20° = 70° looking S
β = 90° - 70° = 20° looking S
When sun is over Tropic of Cancer,
α = 90° - 20° + 23.45° = 93.45° looking S
However, physically this actually means α = [180° - 93.45°= 86.55°] looking N
β = 90° - 86.55° = 3.45° looking N
When sun is over Tropic of Capricorn,
α = 90° - 20° - 23.45° = 46.55° looking S
β = 90° - 46.55° = 43.45° looking S
Fundamental of Solar Photovoltaics Technology - SEDA Malaysia- 3rd edition 2023
Example 4.5
SEDA GCPV Tutorial Fundamental - 28 Nov 2024
Basic Solar Engineering - Question 11